Answers for "binary search a string python"

7

python binary search

def binary_search(arr, item):
	first = 0
	last = len(arr) - 1
	while(first <= last):
		mid = (first + last) // 2
		if arr[mid] == item :
			return True
		elif item < arr[mid]:
			last = mid - 1
		else:
			first = mid + 1	
	return False
Posted by: Guest on September-29-2021
0

binary search python

# This is real binary search
# this algorithm works very good because it is recursive

def binarySearch(arr, min, max, x):
    if max >= min:
        i = int(min + (max - min) / 2) # average
        if arr[i] == x:
            return i
        elif arr[i] < x:
            return binarySearch(arr, i + 1, max, x)
        else:
            return binarySearch(arr, min, i - 1, x)
Posted by: Guest on December-30-2020
0

binary search in python

def binary_search_recursive(list_of_numbers, number, start=0, end=None):

    # The end of our search is initialized to None. First we set the end to the length of the sequence.
    if end is None:
        end = len(list_of_numbers) - 1

    if start > end:
        # This will happen if the list is empty of the number is not found in the list.
        raise ValueError('Number not in list')

    mid = (start + end) // 2  # This is the mid value of our binary search.

    if number == list_of_numbers[mid]:
        # We have found the number in our list. Let's return the index.
        return mid

    if number < list_of_numbers[mid]:
        # Number lies in the lower half. So we call the function again changing the end value to 'mid - 1' Here we are entering the recursive mode.



        return binary_search_recursive(list_of_numbers, number, start, mid - 1)
    # number > list_of_numbers[mid]
    # Number lies in the upper half. So we call the function again changing the start value to 'mid + 1' Here we are entering the recursive mode.

    return binary_search_recursive(list_of_numbers, number, mid + 1, end)
Posted by: Guest on August-20-2021
0

binary search python

# Iterative Binary Search Function
# It returns index of x in given array arr if present,
# else returns -1
def binary_search(arr, x):
    low = 0
    high = len(arr) - 1
    mid = 0
 
    while low <= high:
 
        mid = (high + low) // 2
 
        # If x is greater, ignore left half
        if arr[mid] < x:
            low = mid + 1
 
        # If x is smaller, ignore right half
        elif arr[mid] > x:
            high = mid - 1
 
        # means x is present at mid
        else:
            return mid
 
    # If we reach here, then the element was not present
    return -1
 
 
# Test array
arr = [ 2, 3, 4, 10, 40 ]
x = 10
 
# Function call
result = binary_search(arr, x)
 
if result != -1:
    print("Element is present at index", str(result))
else:
    print("Element is not present in array")
Posted by: Guest on January-16-2022

Python Answers by Framework

Browse Popular Code Answers by Language