datediff in seconds in pandas
t1 = pd.to_datetime('1/1/2015 01:00')
t2 = pd.to_datetime('1/1/2015 03:30')
print pd.Timedelta(t2 - t1).seconds / 3600.0datediff in seconds in pandas
t1 = pd.to_datetime('1/1/2015 01:00')
t2 = pd.to_datetime('1/1/2015 03:30')
print pd.Timedelta(t2 - t1).seconds / 3600.0pandas difference between dates
# credit to Stack Overflow user in the source link
import pandas as pd
# df is your pandas dataframe
# if already datetime64 you don't need to use to_datetime
df['A'] = pd.to_datetime(df['A'])
df['B'] = pd.to_datetime(df['B'])
df['diff'] = df['A'] - df['B'] # difference in daysCopyright © 2021 Codeinu
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