Answers for "fizzbuzz()"

5

fizzbuzz python

def fizz_buzz(num):
    if num % 3 == 0 and num % 5 == 0:
        return "fizzBuzz"
    elif num % 3 == 0:
        return "fizz"
    elif num % 5 == 0:
        return "buzz"
    else:
        return num
Posted by: Guest on December-05-2020
0

fizzbuzz python

for i in range (1,101):
    print("Fizz"*(i%3<1)+(i%5<1)*"buzz" or i)
Posted by: Guest on November-28-2021

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