Answers for "fizzbuzz golang"

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fizzbuzz golang

func fizzBuzz(n int32) {
    var i int32
    var output string
    for i= 1;i <= n; i++{
        output = ""
        if i %3 == 0 {
            output += "Fizz"
        }
        if i %5 == 0 {
            output += "Buzz"
        }
        if output == ""{
            output = fmt.Sprintf("%d", i)
        }
        fmt.Println(output)
    }

}

Posted by: Guest on May-08-2021

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