Answers for "sort dictionary by value and key python descending"

0

python dictionary sort in descending order

dict = {"Python":750,"Java":950,"Ruby":700,"C++":200} 
 
sort_values = sorted(dict.items(), key=lambda y: y[1], reverse=True)

for i in sort_values:
	print(i[0], i[1])
Posted by: Guest on April-23-2022
1

order dictionary by value python

x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
sorted_dict = {k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
print(sorted_dict)
#{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}
Posted by: Guest on June-28-2021

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