python get command line arguments
import sys
print("This is the name of the script:", sys.argv[0])
print("Number of arguments:", len(sys.argv))
print("The arguments are:" , str(sys.argv))
#Example output
#This is the name of the script: sysargv.py
#Number of arguments in: 3
#The arguments are: ['sysargv.py', 'arg1', 'arg2']pass argument to a py file
import sys
def hello(a,b):
print "hello and that's your sum:", a + b
if __name__ == "__main__":
a = int(sys.argv[1])
b = int(sys.argv[2])
hello(a, b)
# If you type : py main.py 1 5
# It should give you "hello and that's your sum:6"read argument from terminal
#!/usr/bin/python
import sys
print 'Number of arguments:', len(sys.argv), 'arguments.'
print 'Argument List:', str(sys.argv)
#Terminal
# $ python test.py arg1 arg2 arg3
#print
#Number of arguments: 4 arguments.
#Argument List: ['test.py', 'arg1', 'arg2', 'arg3']program arguments python
#!/usr/bin/python
import sys
for args in sys.argv:
print(args)
"""
If you were to call the program with subsequent arguments, the output
will be of the following
Call:
python3 sys.py homie no
Output:
sys.py
homie
no
"""how to get command line arguments in python
#!/usr/bin/python
import sys
print 'Number of arguments:', len(sys.argv), 'arguments.'
print 'Argument List:', str(sys.argv)java read file from command line argument
import java.util.Scanner;
import java.io.File;
Scanner input = new Scanner(new File(args[0])); //Where args[0] is the cmd argument, the file nameCopyright © 2021 Codeinu
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