fizzbuzz python
def fizz_buzz(num):
if num % 3 == 0 and num % 5 == 0:
return "fizzBuzz"
elif num % 3 == 0:
return "fizz"
elif num % 5 == 0:
return "buzz"
else:
return numfizzbuzz python
def fizz_buzz(num):
if num % 3 == 0 and num % 5 == 0:
return "fizzBuzz"
elif num % 3 == 0:
return "fizz"
elif num % 5 == 0:
return "buzz"
else:
return numfizz buzz python
def fizz_buzz(input):
if (input % 3 == 0) and (input % 5 == 0):
return "FizzBuzz"
if input % 3 == 0:
return "Fizz"
if input % 5 == 0:
return "Buzz"
else:
return input
print(fizz_buzz(3))fizz buzz python
#made by myself :)
def FizzBuzz() :
Numbers = 0
for Numbers in range(101):
if Numbers%3 == 0:
print ("Fizz")
if Numbers%5 == 0:
print ("Buzz")
if Numbers%3 == 0 and Numbers%5 ==0:
print ("Fizz Buzz")
else :
print (Numbers)
FizzBuzz()fizz buzz python
fizz = 3
buzz = 5
fizzbuzz = fizz * buzz
for i in range(100):
if i % fizzbuzz == o:
print('fizzbuzz')
elif i % fizz == 0:
print('fizz')
elif i % buzz == 0:
print('buzz')
else:
print(i)fizz buzz python
def fizzBuzz(n):
# Write your code here
for i in range(1,a):
if(i%3==0 and i%5!=0):
print("Fizz")
elif(i%5==0 and i%3!=0):
print("Buzz")
elif(i%5==0 and i%3==0):
print(i)
a = int(input("enter the no"))
fizzBuzz(a)fizz buzz python
# changeable game of fizz buzz (all you have to change is n and D
# to add or alter the game.
# No adding or changing if/else required to include bizz at 7 or fuzz at 11
# just insert it into the dictionary. (you could easily make a function out of this)
n = 100
D = {3: 'fizz',
5: 'buzz'}
for x in range(1, n+1): # makes a range as big as we like
out = ''
for k, v in D.items(): # compares each in range with each key in dictionary
if x % k == 0:
out += v # then attaches the associated word onto the output
if not out:
out = x # if the output is still empty, i.e. no listed factors
print(out, end=' ') # the unchanged number becomes the outputCopyright © 2021 Codeinu
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