enumerate in python
languages = ['Python', 'C', 'C++', 'C#', 'Java']
#Bad way
i = 0 #counter variable
for language in languages:
print(i, language)
i+=1
#Good Way
for i, language in enumerate(languages):
print(i, language)enumerate in python
languages = ['Python', 'C', 'C++', 'C#', 'Java']
#Bad way
i = 0 #counter variable
for language in languages:
print(i, language)
i+=1
#Good Way
for i, language in enumerate(languages):
print(i, language)enumerate in Python
>>> for count, value in enumerate(values):
... print(count, value)
...
0 a
1 b
2 cenumerate in python
list1 = ['1', '2', '3', '4']
for index, listElement in enumerate(list1):
#What enumerate does is, it gives you the index as well as the element in an iterable
print(f'{listElement} is at index {index}') # This print statement is just for example output
# This code will give output :
"""
1 is at index 0
2 is at index 1
3 is at index 2
4 is at index 3
"""enumerate in Python
>>> def my_enumerate(sequence, start=0):
... n = start
... for elem in sequence:
... yield n, elem
... n += 1
...enumerate in Python
grocery = ['bread', 'milk', 'butter']
for item in enumerate(grocery):
print(item)
print('\n')
for count, item in enumerate(grocery):
print(count, item)
print('\n')
# changing default start value
for count, item in enumerate(grocery, 100):
print(count, item)enumerate in python
enumerate(iterable, start=0)
Parameters:
Iterable: any object that supports iteration
Start: the index value from which the counter is
to be started, by default it is 0enumerate in python
Return type: < type 'enumerate' >
[(0, 'eat'), (1, 'sleep'), (2, 'repeat')]
[(2, 'g'), (3, 'e'), (4, 'e'), (5, 'k')]Copyright © 2021 Codeinu
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