python sum of digits
def sum_digits(n):
s = 0
while n:
s += n % 10
n //= 10
return spython sum of digits
def sum_digits(n):
s = 0
while n:
s += n % 10
n //= 10
return show to sum digits of a number in python
number = 123 # the number you want to sum the digits of
sum_of_digits = sum(int(digit) for digit in str(number))
print(sum_of_digits)how to sum digits of a number in python
number = 123 # the number you want summed up
sum_of_digits = 0
for digit in str(number):
sum_of_digits += int(digit)
print(sum_of_digits) # printing the final sum of numberfind the digit number sum in a string in python
# Here, first a complex input is used to determine the sum of all the integers in that input.
# Rules : 1
s = input()
c = ""
for i in s:
if i.isdigit():
c += i
sum_d = sum(int(j) for j in c)
print(sum_d)
# Rules : 2
s = input()
c = ""
sum = 0
for i in s:
if i.isdigit():
c += i
for j in c:
sum += int(c)%10
c = int(c)//10
print(sum)
# Sample input: murad#123#$%&*$%!@*34
# Sample output: 13
# Eval method using to problem:
# Problem name: Python Evaluation
# Code
string = eval(input(""))
print()
# Sample Input: print(2 + 3)
# Sample Output: 5sum of digits in a number python
digit_sum = lambda s: sum(int(digit) for digit in str(s)) #without recursion
#sum of digits using recursion
dsum = 0 # we define dsum outside of the function so its value isn't reset every time the function gets called recursivley
def rdigit_sum(s):
global dsum # making dsum 'global' allows us to use it a function
if s: # checks if s has digits to add to dsum
dsum += s%10 # adds the current units digit to dsum
s = s//10 # removes the current units digit
else: # if there are no digits left
s = dsum # this block reassigns s to dsum, then resets dsum to 0 so dsum doesn't already have a value if this function is called more than once in a program
dsum = 0
return s
return rdigit_sum(s) # this is the 'recursive' part of the program that calls the function againCopyright © 2021 Codeinu
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