Answers for "first non repeating character"

first unique character in a string python

class Solution(object):
   def firstUniqChar(self, s):
      """
      :type s: str
      :rtype: int
      """
      frequency = {}
      for i in s:
         if i not in frequency:
            frequency[i] = 1
         else:
            frequency[i] +=1
      for i in range(len(s)):
         if frequency[s[i]] == 1:
            return i
      return -1
ob1 = Solution()
print(ob1.firstUniqChar("people"))
print(ob1.firstUniqChar("abaabba"))

First non repeating character position in a string

# First non repeating character position in a string

def first_non_repeating_letter(str)
    strL = str.downcase
    strL.each_char.with_index do |v, i|
        if strL.index(v) == strL.rindex(v)
            return i
        end
    end
    -1
end

print "First non repeating character position = ", 
	first_non_repeating_letter("abcdcba");  # 3

First non repeating character position in a string

// First non repeating character position in a string
package main

import (
    "fmt";
    "strings"
)

func FirstNonRepeating(str string) int {
  strL := strings.ToLower(str)
  for i:= range str {
    count:=0
    for j:= range str {
      if strL[i] == strL[j] {
        count++
      }
    }
    if count == 1 {
      return i
    }
  }
return -1
}

func main() {
    fmt.Printf("First non repeating character position = %d", 
        FirstNonRepeating("abcdcba"))  // 3
}

First non repeating character position in a string

// First non repeating character position in a string

function first_non_repeating_letter(str) {
  for(var i = 0; i < str.length; i++) {
    if (str.indexOf(str[i]) === str.lastIndexOf(str[i])) {
      return i
    }
  }
  return null
}

console.log("First non repeating character position = " + 
    first_non_repeating_letter("abcdcba"));  //3