Answers for "parse html beatifoulsoup"

1

beautiful soup 4

from bs4 import BeautifulSoup

with open("index.html") as fp:
    soup = BeautifulSoup(fp)

soup = BeautifulSoup("<html>a web page</html>")
Posted by: Guest on June-03-2020
0

beautifulsoup find class

mydivs = soup.findAll("div", {"class": "stylelistrow"})
Posted by: Guest on April-29-2020
0

how to convert response to beautifulsoup object

import requests
from bs4 import BeautifulSoup

url = 'https://www.google.com'

response = requests.get(url)

html_file = BeautifulSoup(response.text, "html.parser")

print(html_file.prettify())
Posted by: Guest on July-13-2020
0

reate the "soup." This is a beautiful soup object:

soup = bs.BeautifulSoup(source,'lxml')
Posted by: Guest on January-07-2021

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