write a bash program to print a given number in reverse order
n=123465
sd=0
rev=0
while [ $n -gt 0 ]
do
sd=$(( $n % 10 ))
rev=$(( $rev * 10 + $sd ))
n=$(( $n / 10 ))
done
echo "Reverse number of entered digit is $rev"write a bash program to print a given number in reverse order
n=123465
sd=0
rev=0
while [ $n -gt 0 ]
do
sd=$(( $n % 10 ))
rev=$(( $rev * 10 + $sd ))
n=$(( $n / 10 ))
done
echo "Reverse number of entered digit is $rev"Copyright © 2021 Codeinu
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