Answers for "query to fetch 50% records from the table."

SQL
0

query to fetch 50% records from the table.

SELECT * 
FROM EmployeeInfo WHERE
EmpID <= (SELECT COUNT(EmpID)/2 from EmployeeInfo);
Posted by: Guest on April-13-2022
0

query to fetch 50% records from the table.

SELECT * 
FROM EmployeeInfo WHERE
EmpID <= (SELECT COUNT(EmpID)/2 from EmployeeInfo);
Posted by: Guest on April-13-2022
0

query to fetch 50% records from the table.

SELECT * 
FROM EmployeeInfo WHERE
EmpID <= (SELECT COUNT(EmpID)/2 from EmployeeInfo);
Posted by: Guest on April-13-2022
0

query to fetch 50% records from the table.

SELECT * 
FROM EmployeeInfo WHERE
EmpID <= (SELECT COUNT(EmpID)/2 from EmployeeInfo);
Posted by: Guest on April-13-2022
0

query to fetch 50% records from the table.

1
SELECT Email FROM EmployeeInfo WHERE NOT REGEXP_LIKE(Email, ‘[A-Z0-9._%+-]+@[A-Z0-9.-]+.[A-Z]{2,4}’, ‘i’);
Posted by: Guest on April-13-2022
0

query to fetch 50% records from the table.

SELECT * 
FROM EmployeeInfo WHERE
EmpID <= (SELECT COUNT(EmpID)/2 from EmployeeInfo);
Posted by: Guest on April-13-2022
0

query to fetch 50% records from the table.

SELECT * 
FROM EmployeeInfo WHERE
EmpID <= (SELECT COUNT(EmpID)/2 from EmployeeInfo);
Posted by: Guest on April-13-2022
0

query to fetch 50% records from the table.

SELECT * 
FROM EmployeeInfo WHERE
EmpID <= (SELECT COUNT(EmpID)/2 from EmployeeInfo);
Posted by: Guest on April-13-2022
0

query to fetch 50% records from the table.

1
SELECT Email FROM EmployeeInfo WHERE NOT REGEXP_LIKE(Email, ‘[A-Z0-9._%+-]+@[A-Z0-9.-]+.[A-Z]{2,4}’, ‘i’);
Posted by: Guest on April-13-2022
0

query to fetch 50% records from the table.

SELECT * 
FROM EmployeeInfo WHERE
EmpID <= (SELECT COUNT(EmpID)/2 from EmployeeInfo);
Posted by: Guest on April-13-2022

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