Answers for "is in array java"

java check if element exists in array

package com.mkyong.core;

import java.util.Arrays;
import java.util.List;

public class StringArrayExample1 {

    public static void main(String[] args) {

        String[] alphabet = new String[]{"A", "B", "C"};

        // Convert String Array to List
        List<String> list = Arrays.asList(alphabet);
        
        if(list.contains("A")){
            System.out.println("Hello A");
        }

    }

}
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array contains java

StringArrayExample1.java

package com.mkyong.core;

import java.util.Arrays;
import java.util.List;

public class StringArrayExample1 {

    public static void main(String[] args) {

        String[] alphabet = new String[]{"A", "B", "C"};

        // Convert String Array to List
        List<String> list = Arrays.asList(alphabet);
        
        if(list.contains("A")){
            System.out.println("Hello A");
        }

    }

}

java check if element exists in array

package com.mkyong.core;

import java.util.Arrays;
import java.util.List;

public class StringArrayExample1 {

    public static void main(String[] args) {

        String[] alphabet = new String[]{"A", "B", "C"};

        // Convert String Array to List
        List<String> list = Arrays.asList(alphabet);
        
        if(list.contains("A")){
            System.out.println("Hello A");
        }

    }

}
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array contains java

StringArrayExample1.java

package com.mkyong.core;

import java.util.Arrays;
import java.util.List;

public class StringArrayExample1 {

    public static void main(String[] args) {

        String[] alphabet = new String[]{"A", "B", "C"};

        // Convert String Array to List
        List<String> list = Arrays.asList(alphabet);
        
        if(list.contains("A")){
            System.out.println("Hello A");
        }

    }

}