Answers for "oroduct of digit divisible by sum of digit c++"

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digit sum c++

//1
	int n = 12345, sum = 0;
    while(n) {
        sum+=n%10;
        n/=10;
    }
    cout << sum; //15
//2
	int n = 12345, sum = 0;
    for (sum = 0; n > 0; sum += n % 10, n /= 10);
    cout << sum; //15
Posted by: Guest on May-10-2021

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