sum of 2 numbers in python
a = int(input("Enter first number:"))
b = int(input("Enter second number:"))
sum = a+b
print(sum)sum of 2 numbers in python
a = int(input("Enter first number:"))
b = int(input("Enter second number:"))
sum = a+b
print(sum)sum of digits in a number python
digit_sum = lambda s: sum(int(digit) for digit in str(s)) #without recursion
#sum of digits using recursion
dsum = 0 # we define dsum outside of the function so its value isn't reset every time the function gets called recursivley
def rdigit_sum(s):
global dsum # making dsum 'global' allows us to use it a function
if s: # checks if s has digits to add to dsum
dsum += s%10 # adds the current units digit to dsum
s = s//10 # removes the current units digit
else: # if there are no digits left
s = dsum # this block reassigns s to dsum, then resets dsum to 0 so dsum doesn't already have a value if this function is called more than once in a program
dsum = 0
return s
return rdigit_sum(s) # this is the 'recursive' part of the program that calls the function againhow to sum digits of a number in python
number = 123 # the number you want to sum the digits of
sum_of_digits = sum(int(digit) for digit in str(number))
print(sum_of_digits)Copyright © 2021 Codeinu
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