Write a function digitsum that calculates the digit sum of an integer. The digit sum of an integer is the sum of all its digits.
function digSum(n) {
let sum = 0;
let str = n.toString();
console.log(parseInt(str.substring(0, 1)));
for (let i = 0; i < str.length; i++) {
sum += parseInt(str.substring(i,i+1));
}
return sum;
}sum the digits of an integer
def getSum(n)
n.digits.sum
end
print "Sum of digits = ", getSum(555);sum the digits of an integer
#include <stdio.h>
int getSum(unsigned long long n) {
int sum = 0;
for (; n; n /= 10)
sum += n % 10;
return sum;
}
int main(){
printf("Sum of digits = %d\n", getSum(555));
}Given a long number, return all the possible sum of two digits of it. For example, 12345: all possible sum of two digits from that number are:
function digits(num){
let numArray = num.toString().split('');
let sumArray = [];
for (let i = 0; i < numArray.length; i++) {
for (let j = i+1; j < numArray.length; j++) {
let sum;
sum = Number(numArray[i]) + Number(numArray[j]);
sumArray.push(sum);
}
}
return sumArray;
}Copyright © 2021 Codeinu
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