armstrong no. C++
#include <iostream> using namespace std; int main() { int num, originalNum, remainder, result = 0; cout << "Enter a three-digit integer: "; cin >> num; originalNum = num; while (originalNum != 0) { // remainder contains the last digit remainder = originalNum % 10; result += remainder * remainder * remainder; // removing last digit from the orignal number originalNum /= 10; } if (result == num) cout << num << " is an Armstrong number."; else cout << num << " is not an Armstrong number."; return 0; }
