armstrong no. C++
#include <iostream>
using namespace std;
int main() {
int num, originalNum, remainder, result = 0;
cout << "Enter a three-digit integer: ";
cin >> num;
originalNum = num;
while (originalNum != 0) {
// remainder contains the last digit
remainder = originalNum % 10;
result += remainder * remainder * remainder;
// removing last digit from the orignal number
originalNum /= 10;
}
if (result == num)
cout << num << " is an Armstrong number.";
else
cout << num << " is not an Armstrong number.";
return 0;
}