c program to check the number is armstrong or not
#include <stdio.h>
#include <math.h>
void main ()
{
int n,t,r,c,s=0;
printf("Enter the number: ");
scanf("%d",&n);
t=n;
while(t!=0)
{
r=t%10;
c=pow(r,3);
s=s+c;
t=t/10;
}
if(s==n)
printf("Armstrong");
else
printf("Not Armstrong");
}armstrong number in c
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int cube(int a)
{
int c;
c = a*a*a;
return c;
}
int armnum(int *a)
{
int x = *a, n = 0, rem, r = 0;
while (x != 0) {
x /= 10;
n++;
}
x = *a;
while (x != 0) {
rem = x % 10;
r += cube(rem);
x /= 10;
}
if(r == *a){
return 1;
}
}
int main()
{
int a, y;
scanf("%d", &a);
y = armnum(&a);
if(y == 1){
printf("It is an Armstrong number.");
}
else{
printf("It is not an Armstrong number.");
}
}Copyright © 2021 Codeinu
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