c program to check the number is armstrong or not
#include <stdio.h>
#include <math.h>
void main ()
{
int n,t,r,c,s=0;
printf("Enter the number: ");
scanf("%d",&n);
t=n;
while(t!=0)
{
r=t%10;
c=pow(r,3);
s=s+c;
t=t/10;
}
if(s==n)
printf("Armstrong");
else
printf("Not Armstrong");
}armstrong number in c
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int cube(int a)
{
int c;
c = a*a*a;
return c;
}
int armnum(int *a)
{
int x = *a, n = 0, rem, r = 0;
while (x != 0) {
x /= 10;
n++;
}
x = *a;
while (x != 0) {
rem = x % 10;
r += cube(rem);
x /= 10;
}
if(r == *a){
return 1;
}
}
int main()
{
int a, y;
scanf("%d", &a);
y = armnum(&a);
if(y == 1){
printf("It is an Armstrong number.");
}
else{
printf("It is not an Armstrong number.");
}
}armstrong number in c
//Bismillahir Rahmanir Rahim
#include <stdio.h>
#include <math.h>
int digit(int n, int count){
while( n != 0){
n/=10;
count++;
}
return count;
}
int main(){
int n, rem, num, sum = 0, count = 0, digits;
while(1){
printf("Enter a number (type 0 to exit) : ");
scanf("%d", &n);
if(n==0){
break;
}
digits = digit(n,count);
num=n;
while(num != 0){
rem = num % 10;
sum += pow(rem,digits);
num /= 10;
}
if(sum == n){
printf("%d is an armstrong number!\n", n);
sum = 0;
}else{
printf("%d is not an armstrong number!\n", n);
sum = 0;
}
}
return 0;
}Copyright © 2021 Codeinu
Forgot your account's password or having trouble logging into your Account? Don't worry, we'll help you to get back your account. Enter your email address and we'll send you a recovery link to reset your password. If you are experiencing problems resetting your password contact us
