Answers for "c# generate random int in range"

C#
5

c# generate random int in range

Random r = new Random();
int rInt = r.Next(0, 100); //for ints
int range = 100;
double rDouble = r.NextDouble()* range; //for doubles
Posted by: Guest on May-26-2020
1

generate range c#

// Generate a sequence of integers from 1 to 10 
// and then select their squares.
IEnumerable<int> squares = Enumerable.Range(1, 10).Select(x => x * x);

foreach (int num in squares)
{
    Console.WriteLine(num);
}

/*
 This code produces the following output:

 1
 4
 9
 16
 25
 36
 49
 64
 81
 100
*/
Posted by: Guest on March-18-2020

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