Answers for "c# create a json object"

C#
2

create json string c#

//Create my object
        var my_jsondata = new
        {
            Host = @"sftp.myhost.gr",
            UserName = "my_username",
            Password = "my_password",
            SourceDir = "/export/zip/mypath/",
            FileName = "my_file.zip"
        };

        //Tranform it to Json object
        string json_data = JsonConvert.SerializeObject(my_jsondata);

        //Print the Json object
        Console.WriteLine(json_data);

        //Parse the json object
        JObject json_object = JObject.Parse(json_data);

        //Print the parsed Json object
        Console.WriteLine((string)json_object["Host"]);
        Console.WriteLine((string)json_object["UserName"]);
        Console.WriteLine((string)json_object["Password"]);
        Console.WriteLine((string)json_object["SourceDir"]);
        Console.WriteLine((string)json_object["FileName"]);
Posted by: Guest on October-22-2020
-1

c# create a json object

dynamic ret = new JObject();

ret = new JObject(new JProperty("vendorDetails", new JObject()));

ret.vendorDetails.Add(new JProperty("vendorName", "Vendor Name"));
Posted by: Guest on April-14-2021

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