deserialize xml c#
// Construct an instance of the XmlSerializer with the type // of object that is being deserialized. var mySerializer = new XmlSerializer(typeof(MySerializableClass)); // To read the file, create a FileStream. using var myFileStream = new FileStream("myFileName.xml", FileMode.Open); // Call the Deserialize method and cast to the object type. var myObject = (MySerializableClass)mySerializer.Deserialize(myFileStream);