Answers for "jsonconvert.deserializeobject list c#"

C#
23

deserialize json to object c#

dynamic json = Newtonsoft.Json.JsonConvert.DeserializeObject(jsonstring);
Posted by: Guest on May-02-2020
0

c# json deserialize list of objects

//using the holy NEWTON! (you can find it as a nuget package)
using Newtonsoft.Json;
//get some storage for your required type
List<YourType> OutputList;

//usings clean up 
//Load some sort of stream (file or memory)
using (Stream Stream = new FileStream(ConfigFile, FileMode.Open))
using (StreamReader SR = new StreamReader(Stream))
using (JsonReader Reader = new JsonTextReader(SR))
            {
                JsonSerializer Serializer = new JsonSerializer();
                OutputList = Serializer.Deserialize<List<YourType>>(Reader);
            }
//bam done
//your type can be anything and can be marked to change names as rquired
public class YourType
{
     [JsonProperty("YourTransactions")]
     public List<Transactions> transactions {get;set;}
     public int count{get;set;}
}
Posted by: Guest on April-08-2021

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