Answers for "c# jsonconvert.deserializeobject"

5

c# serialize json

using System.Text.Json;

//Serialize
var jsonString = JsonSerializer.Serialize(yourObject);

// Deserialize
var obj = JsonSerializer.Deserialize<YourObject>(stringValue);
Posted by: Guest on December-03-2020
10

deserialize json to object c#

dynamic json = Newtonsoft.Json.JsonConvert.DeserializeObject(jsonstring);
Posted by: Guest on May-02-2020
4

java json deserializer

private Car parseCar(JsonNode node) {
        Car car;
        ObjectMapper mapper = new ObjectMapper();
        SimpleModule module = new SimpleModule().addDeserializer(Car.class, new CarDeserializer());
        mapper.registerModule(module);
        organization = mapper.convertValue(node, Car.class);
        return car;
}

//deserializer class
public class CarDeserializer extends StdDeserializer<Car> {

    public CarDeserializer() {
        super(Car.class);
    }

    @Override
    public Car deserialize(JsonParser jsonParser, DeserializationContext deserializationContext) throws IOException {
        ObjectMapper objectMapper = new ObjectMapper();
        objectMapper.registerModule(new JodaModule());

        Car car = new Car();
        car.setName(getValueAsText(root, "carName"));
        car.setDoorCount(getValueAsInt(root,"doorCount"));
        car.setColor(getValueAsText(root,"color"));
		car.setType(getValueAsText(root,"type"));

        return car;
    }

}
Posted by: Guest on November-05-2020
0

c# deserialize json

weatherForecast = JsonSerializer.Deserialize<WeatherForecastWithPOCOs>(jsonString);
Posted by: Guest on September-02-2021

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