Answers for "xpath python"

0

xpath start-with python

$x('//span[@class="text" and starts-with(.,"A")]/text()')
#Delivers texts of certain html element(span here) which start with "A"
$x('//span[@class="text" and ends-with(.,"A")]/text()')
#Delivers texts of certain html element(span here) which ends with "A" ;)
Posted by: Guest on October-08-2021
0

xpath parsing in python

try:
    # Python 2
    from urllib2 import urlopen
except ImportError:
    from urllib.request import urlopen
from lxml import etree

url =  "http://www.example.com/servlet/av/ResultTemplate=AVResult.html"
response = urlopen(url)
htmlparser = etree.HTMLParser()
tree = etree.parse(response, htmlparser)
tree.xpath(xpathselector)
Posted by: Guest on April-18-2021
-2

python xpath html

from lxml import html
import requests
page = requests.get('http://econpy.pythonanywhere.com/ex/001.html')
tree = html.fromstring(page.content)
Posted by: Guest on June-16-2021
0

xpath start-with python

$x('//span[@class="text" and starts-with(.,"A")]/text()')
#Delivers texts of certain html element(span here) which start with "A"
$x('//span[@class="text" and ends-with(.,"A")]/text()')
#Delivers texts of certain html element(span here) which ends with "A" ;)
Posted by: Guest on October-08-2021
0

xpath parsing in python

try:
    # Python 2
    from urllib2 import urlopen
except ImportError:
    from urllib.request import urlopen
from lxml import etree

url =  "http://www.example.com/servlet/av/ResultTemplate=AVResult.html"
response = urlopen(url)
htmlparser = etree.HTMLParser()
tree = etree.parse(response, htmlparser)
tree.xpath(xpathselector)
Posted by: Guest on April-18-2021
-2

python xpath html

from lxml import html
import requests
page = requests.get('http://econpy.pythonanywhere.com/ex/001.html')
tree = html.fromstring(page.content)
Posted by: Guest on June-16-2021

Browse Popular Code Answers by Language