Answers for "Html ask for camera access"

0

Html ask for camera access

if (navigator.mediaDevices.getUserMedia) {
  navigator.mediaDevices.getUserMedia({ video: true })
    .then(function (stream) {
      video.srcObject = stream;
    })
    .catch(function (err0r) {
      console.log("Something went wrong!");
    });
}
Posted by: Guest on May-03-2021
0

Html ask for camera access

var video = document.querySelector("#videoElement");
Posted by: Guest on May-03-2021
0

Html ask for camera access

if (navigator.mediaDevices.getUserMedia) {
  navigator.mediaDevices.getUserMedia({ video: true })
    .then(function (stream) {
      video.srcObject = stream;
    })
    .catch(function (err0r) {
      console.log("Something went wrong!");
    });
}
Posted by: Guest on May-03-2021
0

Html ask for camera access

<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>Display Webcam Stream</title>
 
<style>
#container {
	margin: 0px auto;
	width: 500px;
	height: 375px;
	border: 10px #333 solid;
}
#videoElement {
	width: 500px;
	height: 375px;
	background-color: #666;
}
</style>
</head>
 
<body>
<div id="container">
	<video autoplay="true" id="videoElement">
	
	</video>
</div>
<script>

</script>
</body>
</html>
Posted by: Guest on May-03-2021
0

Html ask for camera access

if (navigator.mediaDevices.getUserMedia) {
  navigator.mediaDevices.getUserMedia({ video: true })
    .then(function (stream) {
      video.srcObject = stream;
    })
    .catch(function (err0r) {
      console.log("Something went wrong!");
    });
}
Posted by: Guest on May-03-2021
0

Html ask for camera access

function stop(e) {
  var stream = video.srcObject;
  var tracks = stream.getTracks();

  for (var i = 0; i < tracks.length; i++) {
    var track = tracks[i];
    track.stop();
  }

  video.srcObject = null;
}
Posted by: Guest on May-03-2021
0

Html ask for camera access

var video = document.querySelector("#videoElement");

if (navigator.mediaDevices.getUserMedia) {
  navigator.mediaDevices.getUserMedia({ video: true })
    .then(function (stream) {
      video.srcObject = stream;
    })
    .catch(function (err0r) {
      console.log("Something went wrong!");
    });
}
Posted by: Guest on May-03-2021

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