Latex in html
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 3.2 Final//EN"> <html> <head> <title>Mathedemo</title> <script type="text/x-mathjax-config"> MathJax.Hub.Config({tex2jax: {inlineMath: [[','], ['\\(','\\)']]}}); </script> <script type="text/javascript" src="http://cdnjs.cloudflare.com/ajax/libs/mathjax/2.7.1/MathJax.js?config=TeX-AMS-MML_HTMLorMML"> </script> </head> <body> <h2>Math in TeX notation</h2> When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are $$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$ $$ \begin{array}{rcll} y & = & x^{2}+bx+c\\ & = & x^{2}+2\times\dfrac{b}{2}x+c\\ & = & \underbrace{x^{2}+2\times\dfrac{b}{2}x+\left(\frac{b}{2}\right)^{2}}- {\left(\dfrac{b}{2}\right)^{2}+c}\\ & & \qquad\left(x+{\dfrac{b}{2}}\right)^{2}\\ & = & \left(x+\dfrac{b}{2}\right)^{2}-\left(\dfrac{b}{2}\right)^{2}+c & \left|+\left({\dfrac{b}{2}}\right)^{2}-c\right.\\ y+\left(\dfrac{b}{2}\right)^{2}-c & = & \left(x+ \dfrac{b}{2}\right)^{2} & \left|\strut(\textrm{vertex form})\right.\\ y-y_{S} & = & (x-x_{S})^{2}\\ S(x_{S};y_{S}) & \,\textrm{or}\, & S\left(-\dfrac{b}{2};\,\left(\dfrac{b}{2}\right)^{2}-c\right) \end{array} $$ <h2>Math in MathML notation</h2> When <math><mi>a</mi><mo>≠</mo><mn>0</mn></math>, there are two solutions to <math> <mi>a</mi><msup><mi>x</mi><mn>2</mn></msup> <mo>+</mo> <mi>b</mi><mi>x</mi> <mo>+</mo> <mi>c</mi> <mo>=</mo> <mn>0</mn> </math> and they are <math mode="display"> <mi>x</mi> <mo>=</mo> <mrow> <mfrac> <mrow> <mo>−</mo> <mi>b</mi> <mo>±</mo> <msqrt> <msup><mi>b</mi><mn>2</mn></msup> <mo>−</mo> <mn>4</mn><mi>a</mi><mi>c</mi> </msqrt> </mrow> <mrow> <mn>2</mn><mi>a</mi> </mrow> </mfrac> </mrow> <mtext>.</mtext> </math> </body> </html>
