sum of all numbers in array java
int[] a = {10,20,30,40,50};
int sum = IntStream.of(a).sum();
System.out.println("The sum is " + sum);sum of all numbers in array java
int[] a = {10,20,30,40,50};
int sum = IntStream.of(a).sum();
System.out.println("The sum is " + sum);java running sum of array
class Solution {
public int[] runningSum(int[] nums) {
int[] sol = new int[nums.length];
sol[0] = nums[0];
for(int i = 1; i < nums.length; i++) {
sol[i] = sol[i-1] + nums[i];
}
return sol;
}
}
// Example: runningSum([1,3,6,9]) = [1, 4, 10, 19] = [1, 1+3, 1+3+6, 1+3+6+9]sum of arrays numbers in java
public static void main(String[] args) {
String str = "a1b2c3d4";
char[] arr = str.toCharArray(); // stringi char array return etti.
System.out.println(Arrays.toString(arr)); // [a, 1, b, 2, c, 3, d, 4]
int sum = 0; // will contain sum of all digits
for(char each : arr ){ // '0'
if( Character.isDigit(each) ){
// isDigit(): identifies if the given character is digit
sum += Integer.parseInt(""+each); }
}
System.out.println(sum); // 10Copyright © 2021 Codeinu
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