js sum of array
[1, 2, 3, 4].reduce((a, b) => a + b, 0)
// Output: 10js sum of array
[1, 2, 3, 4].reduce((a, b) => a + b, 0)
// Output: 10javascript sum of array
const sum = arr => arr.reduce((a, b) => a + b, 0);running sum of array
Input: nums = [1,1,1,1,1]
Output: [1,2,3,4,5]
Explanation: Running sum is obtained as follows: [1, 1+1, 1+1+1, 1+1+1+1, 1+1+1+1+1].Copyright © 2021 Codeinu
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