Answers for "Binary Search tree in java"

binary search java

// Java implementation of iterative Binary Search 
class BinarySearch { 
	// Returns index of x if it is present in arr[], 
	// else return -1 
	int binarySearch(int arr[], int x) 
	{ 
		int l = 0, r = arr.length - 1; 
		while (l <= r) { 
			int m = l + (r - l) / 2; 

			// Check if x is present at mid 
			if (arr[m] == x) 
				return m; 

			// If x greater, ignore left half 
			if (arr[m] < x) 
				l = m + 1; 

			// If x is smaller, ignore right half 
			else
				r = m - 1; 
		} 

		// if we reach here, then element was 
		// not present 
		return -1; 
	} 

	// Driver method to test above 
	public static void main(String args[]) 
	{ 
		BinarySearch ob = new BinarySearch(); 
		int arr[] = { 2, 3, 4, 10, 40 }; 
		int n = arr.length; 
		int x = 10; 
		int result = ob.binarySearch(arr, x); 
		if (result == -1) 
			System.out.println("Element not present"); 
		else
			System.out.println("Element found at "
							+ "index " + result); 
	} 
}

binary search java

binary search program in java.
public class BinarySearchExample
{
   public static void binarySearch(int[] arrNumbers, int start, int end, int keyElement)
   {
      int middle = (start + end) / 2;
      while(start <= end)
      {
         if(arrNumbers[middle] < keyElement)
         {
            start = middle + 1;
         }
         else if(arrNumbers[middle] == keyElement)
         {
            System.out.println("Element found at index: " + middle);
            break;
         }
         else
         {
            end = middle - 1;
         }
         middle = (start + end) / 2;
      }
      if(start > end)
      {
         System.out.println("Element not found!");
      }
   }
   public static void main(String[] args)
   {
      int[] arrNumbers = {14,15,16,17,18};
      int keyElement = 16;
      int end = arrNumbers.length - 1;
      binarySearch(arrNumbers, 0, end, keyElement);
   }
}

binary tree search

/* This is just the seaching function you need to write the required code.
	Thank you. */

void searchNode(Node *root, int data)
{
    if(root == NULL)
    {
        cout << "Tree is empty\n";
        return;
    }

    queue<Node*> q;
    q.push(root);

    while(!q.empty())
    {
        Node *temp = q.front();
        q.pop();

        if(temp->data == data)
        {
            cout << "Node found\n";
            return;
        }

        if(temp->left != NULL)
            q.push(temp->left);
        if(temp->right != NULL)
            q.push(temp->right);
    }

    cout << "Node not found\n";
}

binary search tree operations in java

// Binary Search Tree operations in Java

class BinarySearchTree {
  class Node {
    int key;
    Node left, right;

    public Node(int item) {
      key = item;
      left = right = null;
    }
  }

  Node root;

  BinarySearchTree() {
    root = null;
  }

  void insert(int key) {
    root = insertKey(root, key);
  }

  // Insert key in the tree
  Node insertKey(Node root, int key) {
    // Return a new node if the tree is empty
    if (root == null) {
      root = new Node(key);
      return root;
    }

    // Traverse to the right place and insert the node
    if (key < root.key)
      root.left = insertKey(root.left, key);
    else if (key > root.key)
      root.right = insertKey(root.right, key);

    return root;
  }

  void inorder() {
    inorderRec(root);
  }

  // Inorder Traversal
  void inorderRec(Node root) {
    if (root != null) {
      inorderRec(root.left);
      System.out.print(root.key + " -> ");
      inorderRec(root.right);
    }
  }

  void deleteKey(int key) {
    root = deleteRec(root, key);
  }

  Node deleteRec(Node root, int key) {
    // Return if the tree is empty
    if (root == null)
      return root;

    // Find the node to be deleted
    if (key < root.key)
      root.left = deleteRec(root.left, key);
    else if (key > root.key)
      root.right = deleteRec(root.right, key);
    else {
      // If the node is with only one child or no child
      if (root.left == null)
        return root.right;
      else if (root.right == null)
        return root.left;

      // If the node has two children
      // Place the inorder successor in position of the node to be deleted
      root.key = minValue(root.right);

      // Delete the inorder successor
      root.right = deleteRec(root.right, root.key);
    }

    return root;
  }

  // Find the inorder successor
  int minValue(Node root) {
    int minv = root.key;
    while (root.left != null) {
      minv = root.left.key;
      root = root.left;
    }
    return minv;
  }

  // Driver Program to test above functions
  public static void main(String[] args) {
    BinarySearchTree tree = new BinarySearchTree();

    tree.insert(8);
    tree.insert(3);
    tree.insert(1);
    tree.insert(6);
    tree.insert(7);
    tree.insert(10);
    tree.insert(14);
    tree.insert(4);

    System.out.print("Inorder traversal: ");
    tree.inorder();

    System.out.println("\n\nAfter deleting 10");
    tree.deleteKey(10);
    System.out.print("Inorder traversal: ");
    tree.inorder();
  }
}

insert binary search tree

void BSNode::insert(std::string value) {

	if (this->_data == value) {
		_count++;
		return;
	}

	if (this->_data > value) {
		if (this->getLeft() == nullptr) {
			this->_left = new BSNode(value);
		}
		this->getLeft()->insert(value);
		return;
	}

	if (this->getRight() == nullptr) {
		this->_right = new BSNode(value);
		return;
	}
	this->getRight()->insert(value);
}