Answers for "binary serch tree java"

3

binary search tree insert java

public static Node insert(Node root, int x){
    if (root == null)
        return new Node(x);
    else if(x>root.getData())
        root.setRightChild(insert(root.getRightChild(),x));
    else
        root.setLeftChild(insert(root.getLeftChild(),x));
    return root;
}
Posted by: Guest on June-08-2020
3

java binary tree

public class BinaryTree {

    private int key;

    private BinaryTree left, right;

    /**
     * Simple constructor.
     *
     * @param key
     *     to set as key.
     */
    public BinaryTree(int key) {
        this.key = key;
    }

    /**
     * Extended constructor.
     *
     * @param key
     *     to set as key.
     * @param left
     *     to set as left child.
     * @param right
     *     to set as right child.
     */
    public BinaryTree(int key, BinaryTree left, BinaryTree right) {
        this.key = key;
        setLeft(left);
        setRight(right);
    }

    public int getKey() {
        return key;
    }

    /**
     * @return the left child.
     */
    public BinaryTree getLeft() {
        return left;
    }

    /**
     * @return the right child.
     */
    public BinaryTree getRight() {
        return right;
    }

    public boolean hasLeft() {
        return left != null;
    }

    public boolean hasRight() {
        return right != null;
    }

    //Return a String representation of the BinaryTree using level order traversal
    public String toString(){
        int h = height(this);
        int i;
        String result = "";
        for (i=1; i<=h; i++) {
            result += printGivenLevel(this, i);
        }
        return result;
    }

    //returns the number of nodes in the BinaryTree
    public int size(){
        return size(this);
    }

    public static int size(BinaryTree tree){
        if(tree == null) return 0;
        return 1 + size(tree.getLeft()) + size(tree.getRight());
    }

    public int height(){ return height(this);}

    public static int height(BinaryTree tree){
        if(tree == null) return 0;
        int left = height(tree.getLeft());
        int right = height(tree.getRight());
        return Math.max(left, right) + 1;
    }

    public String printGivenLevel (BinaryTree root ,int level) {
        if (root == null) return "";
        String result = "";
        if (level == 1) {
            result += root.getKey() + " ";
            return result;
        }else if (level > 1) {
            String left = printGivenLevel(root.left, level-1);
            String right = printGivenLevel(root.right, level-1);
            return left + right;
        }else{
            return "";
        }
    }

    /**
     * @param left
     *     to set
     */
    public void setLeft(BinaryTree left) {
        this.left = left;
    }

    /**
     * @param right
     *     to set
     */
    public void setRight(BinaryTree right) {
        this.right = right;
    }
}
Posted by: Guest on June-16-2020
11

binary tree search

/* This is just the seaching function you need to write the required code.
	Thank you. */

void searchNode(Node *root, int data)
{
    if(root == NULL)
    {
        cout << "Tree is empty\n";
        return;
    }

    queue<Node*> q;
    q.push(root);

    while(!q.empty())
    {
        Node *temp = q.front();
        q.pop();

        if(temp->data == data)
        {
            cout << "Node found\n";
            return;
        }

        if(temp->left != NULL)
            q.push(temp->left);
        if(temp->right != NULL)
            q.push(temp->right);
    }

    cout << "Node not found\n";
}
Posted by: Guest on June-07-2020

Code answers related to "Java"

Java Answers by Framework

Browse Popular Code Answers by Language