Answers for "write a program to find the maximum and minimum value of an array"

3

Java program to find maximum and minimum number without using array

// Java program to find maximum and minimum number without using array
import java.util.Scanner;
public class MaximumMinimumWithoutArray
{
   public static void main(String[] args)
   {
      Scanner sc = new Scanner(System.in);
      System.out.println("Please enter total number: ");
      int numbers = sc.nextInt();
      int maximum = Integer.MIN_VALUE;
      int minimum = Integer.MAX_VALUE;
      System.out.println("Please enter " + numbers + " numbers.");
      for(int a = 0; a < numbers; a++)
      {
         int current = sc.nextInt();
         if(current > maximum)
         {
            maximum = current;
         }
         if(current < minimum)
         {
            minimum = current;
         }
      }
      System.out.println("largest of " + numbers + " numbers is: " + maximum);
      System.out.println("smallest of " + numbers + " numbers is: " + minimum);
      sc.close();
   }
}
Posted by: Guest on February-22-2021
1

Minimum and maximum element in an Array

def divideAndConquer_Max(arr, ind, len):
	maximum = -1;

	if (ind >= len - 2):
		if (arr[ind] > arr[ind + 1]):
			return arr[ind];
		else:
			return arr[ind + 1];


	maximum = divideAndConquer_Max(arr, ind + 1, len);

	if (arr[ind] > maximum):
		return arr[ind];
	else:
		return maximum;


def divideAndConquer_Min(arr, ind, len):
	minimum = 0;
	if (ind >= len - 2):
		if (arr[ind] < arr[ind + 1]):
			return arr[ind];
		else:
			return arr[ind + 1];

	minimum = divideAndConquer_Min(arr, ind + 1, len);

	if (arr[ind] < minimum):
		return arr[ind];
	else:
		return minimum;


if __name__ == '__main__':

	minimum, maximum = 0, -1;

	# array initialization
	arr = [6, 4, 8, 90, 12, 56, 7, 1, 63];

	maximum = divideAndConquer_Max(arr, 0, 9);
	minimum = divideAndConquer_Min(arr, 0, 9);

	print("The minimum number in the array is: ", minimum);
	print("The maximum number in the array is: ", maximum);
Posted by: Guest on August-12-2021

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