java array check duplicates
duplicates = false;
for(i = 0; i < zipcodeList.length; i++) {
for(j = i + 1; k < zipcodeList.length; j++) {
if(j != i && zipcodeList[j] == zipcodeList[i]) {
duplicates = true;
}
}
}java array check duplicates
duplicates = false;
for(i = 0; i < zipcodeList.length; i++) {
for(j = i + 1; k < zipcodeList.length; j++) {
if(j != i && zipcodeList[j] == zipcodeList[i]) {
duplicates = true;
}
}
}find repeated elements in array java
for (String name : names) {
if (set.add(name) == false) {
// your duplicate element
}
}find duplicate elements in array in java
/*This method is all in one
*you can find following things:
*finding Duplicate elements in array
*array without duplicate elements
*number of duplicate elements
*numbers of pair of dulicate with repeatation
*/
//let given array = [2,3,2,5,3]
public static void findDuplicateArray(int [] array)
{
int size = array.length;
//creating array to hold count frequency of array elements
int [] countFrequency = new int[size];
// filling countFrequency with -1 value on every index
for(int i = 0; i < size; i++)
{
countFrequency[i] = -1;//[-1,-1,-1,-1,-1...]
}
int count = 1;
for(int i = 0; i < size; i++)
{
//check countFrequency[i] != 0 because 0 means it already counted
if(countFrequency[i] != 0)
{
for(int j = i+1; j < size; j++)
{
//if array[i] == array[j] then increase count value
if(array[i] == array[j])
{
count++;
/*only at first occurence of an element count value
*will be increased else everywhere it will be 0
*/
countFrequency[j]= 0;
}
}
countFrequency[i] = count;
}
count = 1;
}
// array = [2,3,2,5,3]
//countFrequency = [2,2,0,1,0]
System.out.println("array without duplicate elements");
for(int i = 0; i < array.length; i++)
{
if(countFrequency[i] >= 1)
System.out.print(array[i] + " ");
}
System.out.println();
System.out.println("duplicate elements in array");
for(int i = 0; i < array.length; i++)
{
if(countFrequency[i]/2 >= 1)
System.out.print(array[i] + " ");
}
System.out.println();
System.out.println("number of duplicate elements");
count = 0;
for(int i = 0; i < array.length; i++)
{
if(countFrequency[i]/2 >= 1)
count++;
}
System.out.print(count);
System.out.println();
System.out.println("numbers of pair of dulicate with repeatation");
count = 0;
for(int i = 0; i < array.length; i++)
{
if(countFrequency[i] >= 2)
{
int div = countFrequency[i]/2;
count+=div;
}
}
System.out.println(count);
int [] array3 = new int [array.length];
for(int i = 0; i < array.length; i++)
{
for(int j = 0; j < countFrequency[i]; j++)
{
array3[i]= array[i];
}
}
}Copyright © 2021 Codeinu
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