find duplicate in an array using xor
int DuplicateNumber(int arr[], int size){
int ans=0;
for(int i=0;i<size;i++){
ans= ans ^ arr[i] ;
}
for(int i=0;i<=size-2;i++){
ans= ans ^ i;
}
return ans;
}find duplicate in an array using xor
int DuplicateNumber(int arr[], int size){
int ans=0;
for(int i=0;i<size;i++){
ans= ans ^ arr[i] ;
}
for(int i=0;i<=size-2;i++){
ans= ans ^ i;
}
return ans;
}find duplicate in an array using xor
int DuplicateNumber(int arr[], int size){
/* Don't write main().
* Don't read input, it is passed as function argument.
* Return output and don't print it.
* Taking input and printing output is handled automatically.
*/
int ans=0;
for(int i=0;i<size;i++){
ans= ans ^ arr[i] ;
}
for(int i=0;i<=size-2;i++){
ans= ans ^ i;
}
return ans;
}Copyright © 2021 Codeinu
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