java array check duplicates
duplicates = false;
for(i = 0; i < zipcodeList.length; i++) {
for(j = i + 1; k < zipcodeList.length; j++) {
if(j != i && zipcodeList[j] == zipcodeList[i]) {
duplicates = true;
}
}
}
java array check duplicates
duplicates = false;
for(i = 0; i < zipcodeList.length; i++) {
for(j = i + 1; k < zipcodeList.length; j++) {
if(j != i && zipcodeList[j] == zipcodeList[i]) {
duplicates = true;
}
}
}
find duplicates in array
function findDuplicates(arr) {
const duplicates = new Set()
return arr.filter(item => {
if (duplicates.has(item)) {
return true
}
duplicates.add(item)
return false
})
}
javascript find duplicate in array
// JavaScript - finds if there is duplicate in an array.
// Returns True or False.
const isThereADuplicate = function(arrayOfNumbers) {
// Create an empty associative array or hash.
// This is preferred,
let counts = {};
// // but this also works. Comment in below and comment out above if you want to try.
// let counts = [];
for(var i = 0; i <= arrayOfNumbers.length; i++) {
// As the arrayOfNumbers is being iterated through,
// the counts hash is being populated.
// Each value in the array becomes a key in the hash.
// The value assignment of 1, is there to complete the hash structure.
// Once the key exists, meaning there is a duplicate, return true.
// If there are no duplicates, the if block completes and returns false.
if(counts[arrayOfNumbers[i]] === undefined) {
counts[arrayOfNumbers[i]] = 1;
} else {
return true;
}
}
return false;
}
Find duplicate or repeat elements in js array
function findUniq(arr) {
return arr.find(n => arr.indexOf(n) === arr.lastIndexOf(n));
}
console.log(findUniq([ 0, 1, 0 ]))
console.log(findUniq([ 1, 1, 1, 2, 1, 1 ]))
console.log(findUniq([ 3, 10, 3, 3, 3 ]))
console.log(findUniq([ 7, 7, 7, 20, 7, 7, 7 ]))
find duplicate values in array javascript
const findDuplicates = (arr) => {
let sorted_arr = arr.slice().sort(); // You can define the comparing function here.
// JS by default uses a crappy string compare.
// (we use slice to clone the array so the
// original array won't be modified)
let results = [];
for (let i = 0; i < sorted_arr.length - 1; i++) {
if (sorted_arr[i + 1] == sorted_arr[i]) {
results.push(sorted_arr[i]);
}
}
return results;
}
let duplicatedArray = [9, 4, 111, 2, 3, 9, 4, 5, 7];
console.log(`The duplicates in ${duplicatedArray} are ${findDuplicates(duplicatedArray)}`);
Find duplicate or repeat elements in js array
const a = [4,3,6,3,4,3]
function count_duplicate(a){
let counts = {}
for(let i =0; i < a.length; i++){
if (counts[a[i]]){
counts[a[i]] += 1
} else {
counts[a[i]] = 1
}
}
for (let prop in counts){
if (counts[prop] >= 2){
console.log(prop + " counted: " + counts[prop] + " times.")
}
}
console.log(counts)
}
count_duplicate(a)
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