Answers for "java find duplicates in list"

2

java 8 get duplicates in list

List<Integer> numbers = Arrays.asList(1, 2, 1, 3, 4, 4);
Set<Integer> nbrRemovedSet = new HashSet<>();

// Set.add() returns false if the element was already in the set.
Set<Integer> nbrSet = numbers
	.stream()
  	.filter(n -> !nbrRemovedSet.add(n))
  	.collect(Collectors.toSet());

// also, we can use Collections.frequency:
Set<Integer> nbrSet = numbers
	.stream()
  	.filter(i -> Collections.frequency(numbers, i) >1)
    collect(Collectors.toSet());
Posted by: Guest on February-18-2021
4

java array check duplicates

duplicates = false;

for(i = 0; i < zipcodeList.length; i++) {
	for(j = i + 1; k < zipcodeList.length; j++) {
  		if(j != i && zipcodeList[j] == zipcodeList[i]) {
   	  		duplicates = true;
		}
	}
}
Posted by: Guest on February-15-2020
0

java find duplicate element in list

public static Set<String> findDuplicates(List<String> listContainingDuplicates) {
 
		final Set<String> setToReturn = new HashSet<String>();
		final Set<String> set1 = new HashSet<String>();
 
		for (String yourInt : listContainingDuplicates) {
			if (!set1.add(yourInt)) {
				setToReturn.add(yourInt);
			}
		}
		return setToReturn;
	}
Posted by: Guest on November-14-2020
1

java find duplicates in array

// Uses a set, which does not allow duplicates 

for (String name : names) 
{
     if (set.add(name) == false) 
     {
        // print name your duplicate element
     }
}
Posted by: Guest on May-09-2020
-1

Java find duplicate items

System.out.print("Duplicate Characters in above string are: ");
for (int i = 0; i < str.length(); i++) {
   for (int j = i + 1; j < str.length(); j++) {
      if (carray[i] == carray[j]) {
         System.out.print(carray[j] + " ");
         break;
      }
   }
}
Posted by: Guest on June-05-2021

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