java 8 get duplicates in list
List<Integer> numbers = Arrays.asList(1, 2, 1, 3, 4, 4);
Set<Integer> nbrRemovedSet = new HashSet<>();
// Set.add() returns false if the element was already in the set.
Set<Integer> nbrSet = numbers
.stream()
.filter(n -> !nbrRemovedSet.add(n))
.collect(Collectors.toSet());
// also, we can use Collections.frequency:
Set<Integer> nbrSet = numbers
.stream()
.filter(i -> Collections.frequency(numbers, i) >1)
collect(Collectors.toSet());Java find duplicate items
System.out.print("Duplicate Characters in above string are: ");
for (int i = 0; i < str.length(); i++) {
for (int j = i + 1; j < str.length(); j++) {
if (carray[i] == carray[j]) {
System.out.print(carray[j] + " ");
break;
}
}
}java 8 get duplicates in list
List<Integer> numbers = Arrays.asList(1, 2, 1, 3, 4, 4);
Set<Integer> nbrRemovedSet = new HashSet<>();
// Set.add() returns false if the element was already in the set.
Set<Integer> nbrSet = numbers
.stream()
.filter(n -> !nbrRemovedSet.add(n))
.collect(Collectors.toSet());
// also, we can use Collections.frequency:
Set<Integer> nbrSet = numbers
.stream()
.filter(i -> Collections.frequency(numbers, i) >1)
collect(Collectors.toSet());Java find duplicate items
System.out.print("Duplicate Characters in above string are: ");
for (int i = 0; i < str.length(); i++) {
for (int j = i + 1; j < str.length(); j++) {
if (carray[i] == carray[j]) {
System.out.print(carray[j] + " ");
break;
}
}
}Copyright © 2021 Codeinu
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