sort array java
Here’s the java program to sort an array using Arrays.sort() method.
import java.util.Arrays;
public class JavaArraySortMethod
{
public static void main(String[] args)
{
String[] strGiven = {"Great Barrier Reef", "Paris", "borabora", "Florence","tokyo", "Cusco"};
Arrays.sort(strGiven);
System.out.println("Output(case sensitive) : " + Arrays.toString(strGiven));
}
}how to sort integer array in java
int countOfArray = 5;
int num [] = new int[counfOfArray];
int num[] = [8 , 5 , 9 , 3 , 4];
for (int i = 0; i < countOfArray; i++)
{
for (int j = i + 1; j < countOfArray; j++) {
if (num[i] > num[j])
{
temp = num[i];
num[i] = num[j];
num[j] = temp;
}
}
}java sort int array
// an array of ints
int[] arr = {1, 2, 3, 4, 5, 6};
// an array of reverse sorted ints
int[] arrDesc = Arrays.stream(arr).boxed()
.sorted(Collections.reverseOrder())
.mapToInt(Integer::intValue)
.toArray();
System.out.println(Arrays.toString(arrDesc)); // outputs [6, 5, 4, 3, 2, 1]how to sort an array
import java.util.Scanner;
public class JavaExample
{
public static void main(String[] args)
{
int count, temp;
//User inputs the array size
Scanner scan = new Scanner(System.in);
System.out.print("Enter number of elements you want in the array: ");
count = scan.nextInt();
int num[] = new int[count];
System.out.println("Enter array elements:");
for (int i = 0; i < count; i++)
{
num[i] = scan.nextInt();
}
scan.close();
for (int i = 0; i < count; i++)
{
for (int j = i + 1; j < count; j++) {
if (num[i] > num[j])
{
temp = num[i];
num[i] = num[j];
num[j] = temp;
}
}
}
System.out.print("Array Elements in Ascending Order: ");
for (int i = 0; i < count - 1; i++)
{
System.out.print(num[i] + ", ");
}
System.out.print(num[count - 1]);
}
}Copyright © 2021 Codeinu
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