swap of two numbers without using third variable
a=20;
b=40;
a=a+b;
b=a-b;
a=a-b;
swap of two numbers without using third variable
a=20;
b=40;
a=a+b;
b=a-b;
a=a-b;
swap 2 numbers without using 3rd variable
a=10;
b=20;
a=a+b;//a=30 (10+20)
b=a-b;//b=10 (30-20)
a=a-b;//a=20 (30-10)
swap two variables without temporary java
import java.*;
class noTemp {
public static void main(String a[])
{
int x = 10;
int y = 5;
x = x + y;
y = x - y;
x = x - y;
System.out.println("After swaping:"
+ " x = " + x + ", y = " + y);
}
}
swap 2 integers without using temporary variable
using System;
class MainClass {
public static void Main (string[] args) {
int num1 = int.Parse(Console.ReadLine());
int num2 = int.Parse(Console.ReadLine());
num1 = num1 + num2;
num2 = num1 - num2;
num1 = num1 - num2;
Console.WriteLine("After swapping: num1 = "+ num1 + ", num2 = " + num2);
Console.ReadLine();
}
}
how to swap 2 numbers without 3rd variable
int a = 3;
int b = 5;
a = b*a;
b = a/b
a = a/b
swap two numbers without using third variable
var a=window.prompt('enter a number')var b=window.prompt('enter a number')var a=a+b;var b=a-b;var a=a-b;console.log ("value of a is",a);console.log('value of b is',b);
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