Answers for "objects.filter multiple conditions"

2

how to add multiple filter condition in Java stream filter chain

import java.util.ArrayList;
import java.util.List;
import java.util.function.Predicate;
import java.util.stream.Collectors;
 
public class Main 
{
    public static void main(String[] args) 
    {
        List<Employee> employeeList = getEmployeesFromDataSource();
         
        //filter 1
        Predicate<Employee> isEmployeeActive = e -> e.getStatus() == EmployeeStatus.ACTIVE;
 
        //filter2
        Predicate<Employee> isAccountActive = e -> e.getAccount().getStatus() == AccountStatus.ACTIVE;
         
        //Active employees
        String result = employeeList.stream()
                .filter(isEmployeeActive)
                .map(e -> e.getId().toString())
                .collect(Collectors.joining(",", "[", "]"));
         
        System.out.println("Active employees = " + result);
         
        //Active employees with active accounts
        result = employeeList.stream()
                .filter(isEmployeeActive.and(isAccountActive))
                .map(e -> e.getId().toString())
                .collect(Collectors.joining(",", "[", "]"));
         
        System.out.println("Active employees with active accounts = " + result);
         
        //Active employees with inactive accounts
        result = employeeList.stream()
                .filter(isEmployeeActive.and(isAccountActive.negate()))
                .map(e -> e.getId().toString())
                .collect(Collectors.joining(",", "[", "]"));
         
        System.out.println("Active employees with inactive accounts = " + result);
         
        //Inactive employees with inactive accounts
        result = employeeList.stream()
                .filter(isEmployeeActive.negate().and(isAccountActive.negate()))
                .map(e -> e.getId().toString())
                .collect(Collectors.joining(",", "[", "]"));
         
        System.out.println("Inactive employees with inactive accounts = " + result);
    }
     
    private static List<Employee> getEmployeesFromDataSource() {
        List<Employee> employeeList = new ArrayList<>();
         
        employeeList.add(new Employee(1L, "A", "AA", EmployeeStatus.ACTIVE, 
                new Account(1001L, "Saving - 1001", "Saving", AccountStatus.ACTIVE)));
        employeeList.add(new Employee(2L, "B", "BB", EmployeeStatus.ACTIVE, 
                new Account(1002L, "Checking - 1002", "Checking", AccountStatus.ACTIVE)));
        employeeList.add(new Employee(3L, "C", "CC", EmployeeStatus.ACTIVE, 
                new Account(1003L, "Deposit - 1003", "Deposit", AccountStatus.ACTIVE)));
        employeeList.add(new Employee(4L, "D", "DD", EmployeeStatus.ACTIVE, 
                new Account(1004L, "Saving - 1004", "Saving", AccountStatus.INACTIVE)));
        employeeList.add(new Employee(5L, "E", "EE", EmployeeStatus.ACTIVE, 
                new Account(1005L, "Checking - 1005", "Checking", AccountStatus.INACTIVE)));
        employeeList.add(new Employee(6L, "F", "FF", EmployeeStatus.ACTIVE, 
                new Account(1006L, "Deposit - 1006", "Deposit", AccountStatus.BLOCKED)));
         
        return employeeList;
    }
}
Posted by: Guest on June-18-2020
1

filter out object in array using two arguments

var arr= [{id: "123", name: "Faa"},
          {id: "123", name: "Bar"},
          {id: "345", name: "Foo"},
          {id: "678", name: "FaaBar"}
         ];

var name = 'FaaBar';
var id = '678';

arr = arr.filter(function(elem) {
  //return false for the element that matches both the name and the id
  return !(elem.id == id && elem.name == name)
});
Posted by: Guest on June-25-2020

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