java leap year expression
(year % 4 == 0) && ((year % 100 != 0) || (year % 400 == 0))
java leap year expression
(year % 4 == 0) && ((year % 100 != 0) || (year % 400 == 0))
Leap year or not program in java using if-else
import java.util.Scanner;public class Main{public static void main(String[] args){int year;System.out.println("Enter the year");Scanner sc = new Scanner(System.in);year = sc.nextInt();if (((year % 4 == 0) && (year % 100!= 0)) || (year%400 == 0))System.out.println("it is a leap year");elseSystem.out.println("it is not a leap year");}}
Java program to find if given year is leap year
import java.util.Scanner;
public class LeapYearDemo
{
public static void main(String[] args)
{
Scanner sc = new Scanner(System.in);
System.out.println("Please enter any year: ");
int year = sc.nextInt();
boolean temp = false;
if(year % 400 == 0)
{
temp = true;
}
else if(year % 100 == 0)
{
temp = false;
}
else if(year % 4 == 0)
{
temp = true;
}
else
{
temp = false;
}
if(temp)
{
System.out.println("Year " + year + " is a Leap Year");
}
else
{
System.out.println("Year " + year + " is not a Leap Year");
}
sc.close();
}
}
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