Answers for "java check for leap year"

0

check leap year using time in java

import java.time.LocalDate;
import java.time.LocalDateTime;
import java.time.Year;
import java.time.ZonedDateTime;
 
public class Main 
{
    public static void main(String[] args) 
    {
        // 1. ZonedDateTime
 
        ZonedDateTime currentTime = ZonedDateTime.now();
 
        if (currentTime.toLocalDate().isLeapYear()) 
        {
            System.out.println(currentTime.getYear() + " is a leap year");
        } else {
            System.out.println(currentTime.getYear() + " is NOT a leap year");
        }
 
        // 2. LocalDateTime
 
        LocalDateTime localDateTime = LocalDateTime.now();
 
        if (localDateTime.toLocalDate().isLeapYear()) 
        {
            System.out.println(localDateTime.getYear() + " is a leap year");
        } else {
            System.out.println(localDateTime.getYear() + " is NOT a leap year");
        }
         
        // 3. LocalDate
 
        LocalDate localDate = LocalDate.now();
 
        if (localDate.isLeapYear()) 
        {
            System.out.println(localDate.getYear() + " is a leap year");
        } else {
            System.out.println(localDate.getYear() + " is NOT a leap year");
        }
         
        //4. Check current year is leap year or not
 
        if (Year.now().isLeap()) 
        {
            System.out.println("Current year is a leap year");
        } else {
            System.out.println("Current year is NOT a leap year");
        }
    }
}
Posted by: Guest on December-04-2020
-1

java code leap year

import java.util.Scanner;
public class leapyear {
    public static void main(String[] args)
    {
        Scanner myScanner = new Scanner(System.in);
        System.out.println("Enter in the year ");
        int year=myScanner.nextInt();

        if(year%4==0)
            if(year%100==0)
                if(year%400==0)
                    System.out.println("It is a leap year");
                else
                    System.out.println("it is not a leap year");
            else System.out.println("It is a leap year");
        else
            System.out.println("Is not a leap year");
Posted by: Guest on September-13-2020

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