Answers for "java random.nextint range"

20

java random numbers in specific range

import java.util.Random;

Random rand = new Random();
int random_integer = rand.nextInt(upperbound-lowerbound) + lowerbound;
Posted by: Guest on May-21-2020
1

how to get random number in java in range

package com.mkyong.example.test;

import java.util.Random;

public class TestRandom {

    public static void main(String[] args) {

        for (int i = 0; i < 10; i++) {
            System.out.println(getRandomNumberInRange(5, 10));
        }

    }

    private static int getRandomNumberInRange(int min, int max) {

        if (min >= max) {
            throw new IllegalArgumentException("max must be greater than min");
        }

        Random r = new Random();
        return r.nextInt((max - min) + 1) + min;
    }

}
Posted by: Guest on January-20-2021
1

java generate random integer in range

import java.util.concurrent.ThreadLocalRandom;

// nextInt is normally exclusive of the top value,
// so add 1 to make it inclusive
int randomNum = ThreadLocalRandom.current().nextInt(min, max + 1);
Posted by: Guest on October-26-2020
2

java random number generator in range

int rand = ThreadLocalRandom.current().nextInt(x,y);
Posted by: Guest on May-12-2020
0

java random.nextint

public class Random {
  
  public static void main(String[] args) {
    
    Random random = new Random(long seed);
    int bound = 5;
    
    System.out.println(random.nextInt(bound));
    
  }
  
}
/*
Returns a pseudorandom, uniformly distributed int value between
0 (inclusive) and
the specified value 5 (exclusive),
drawn from this random number generator's sequence.
Posted by: Guest on October-10-2020

Code answers related to "Java"

Java Answers by Framework

Browse Popular Code Answers by Language