Answers for "random.nextint range java"

20

java random numbers in specific range

import java.util.Random;

Random rand = new Random();
int random_integer = rand.nextInt(upperbound-lowerbound) + lowerbound;
Posted by: Guest on May-21-2020
2

java random number generator in range

int rand = ThreadLocalRandom.current().nextInt(x,y);
Posted by: Guest on May-12-2020
0

java random.nextint

public class Random {
  
  public static void main(String[] args) {
    
    Random random = new Random(long seed);
    int bound = 5;
    
    System.out.println(random.nextInt(bound));
    
  }
  
}
/*
Returns a pseudorandom, uniformly distributed int value between
0 (inclusive) and
the specified value 5 (exclusive),
drawn from this random number generator's sequence.
Posted by: Guest on October-10-2020

Code answers related to "Java"

Java Answers by Framework

Browse Popular Code Answers by Language