Answers for "display all the Armstrong number in a given range in Java"

3

Java program to print all armstrong numbers between given range

// Java program to print all armstrong numbers between given range
import java.util.Scanner;
public class ArmstrongNumbersGivenRange 
{
   public static void main(String[] args) 
   {
      int number, startNumber, endNumber, a, rem, n, count = 0;
      Scanner sc = new Scanner(System.in);
      System.out.println("Please enter starting number range: ");
      startNumber = sc.nextInt();
      System.out.println("Please enter ending number range: ");
      endNumber = sc.nextInt();
      for(a = startNumber + 1; a < endNumber; a++)
      {
         n = a;
         number = 0;
         while(n != 0)
         {
            rem = n % 10;
            number = number + rem * rem * rem;
            n = n / 10;
         }
         if(a == number)
         {
            if(count == 0)
            {
               System.out.println("Armstrong numbers between given range " + startNumber + " and " + endNumber + ": ");
            }
            System.out.print(a + "  ");
            count++;
         }
      }
      // if there is no Armstrong number found between range
      if(count == 0)
      {
         System.out.println("Sorry!! There's no armstrong number between given range " + startNumber + " and " + endNumber);
      }
      sc.close();
   }
}
Posted by: Guest on February-22-2021
3

4 digit armstrong number in java

// 4 digit armstrong number in java
public class ArmstrongNumberDemo
{
   public static void main(String[] args) 
   {
      int num = 9474, realNumber, remainder, output = 0, a = 0;
      realNumber = num;
      for(;realNumber != 0; realNumber /= 10, ++a);
      realNumber = num;
      for(;realNumber != 0; realNumber /= 10)
      {
         remainder = realNumber % 10;
         output += Math.pow(remainder, a);
      }
      if(output == num)
      {
         System.out.println(num + " is an Armstrong number.");
      }
      else
      {
         System.out.println(num + " is not an Armstrong number.");
      }
   }
}
Posted by: Guest on February-18-2021

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