how to flatten array with reduce in javascript
let flattened = [[0, 1], [2, 3], [4, 5]].reduce(
function(accumulator, currentValue) {
return accumulator.concat(currentValue)
},
[]
)
// flattened is [0, 1, 2, 3, 4, 5]how to flatten array with reduce in javascript
let flattened = [[0, 1], [2, 3], [4, 5]].reduce(
function(accumulator, currentValue) {
return accumulator.concat(currentValue)
},
[]
)
// flattened is [0, 1, 2, 3, 4, 5]javascript sum of array
const sum = arr => arr.reduce((a, b) => a + b, 0);javascript reduce
var array = [36, 25, 6, 15];
array.reduce(function(accumulator, currentValue) {
return accumulator + currentValue;
}, 0); // 36 + 25 + 6 + 15 = 82javascript reduce sum
let nums = [1, 2, 3];
nums.reduce((curr, next) => curr + next);reduce object to array javascript
var arr = [{x:1},{x:2},{x:4}];
arr.reduce(function (a, b) {
return {x: a.x + b.x}; // returns object with property x
})
// ES6
arr.reduce((a, b) => ({x: a.x + b.x}));
// -> {x: 7}how to use reduce in javascript
const sum = array.reduce((accumulator, element) => {
return accumulator + element;
}, 0);
// An example that will loop through an array adding
// each element to an accumulator and returning it
// The 0 at the end initializes accumulator to start at 0
// If array is [2, 4, 6], the returned value in sum
// will be 12 (0 + 2 + 4 + 6)
const product = array.reduce((accumulator, element) => {
return accumulator * element;
}, 1);
// Multiply all elements in array and return the total
// Initialize accumulator to start at 1
// If array is [2, 4, 6], the returned value in product
// will be 48 (1 * 2 * 4 * 6)Copyright © 2021 Codeinu
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