javascript sum of array
const sum = arr => arr.reduce((a, b) => a + b, 0);javascript sum of array
const sum = arr => arr.reduce((a, b) => a + b, 0);javascript reduce
var array = [36, 25, 6, 15];
array.reduce(function(accumulator, currentValue) {
return accumulator + currentValue;
}, 0); // 36 + 25 + 6 + 15 = 82how to use reduce in javascript
const sum = array.reduce((accumulator, element) => {
return accumulator + element;
}, 0);
// An example that will loop through an array adding
// each element to an accumulator and returning it
// The 0 at the end initializes accumulator to start at 0
// If array is [2, 4, 6], the returned value in sum
// will be 12 (0 + 2 + 4 + 6)
const product = array.reduce((accumulator, element) => {
return accumulator * element;
}, 1);
// Multiply all elements in array and return the total
// Initialize accumulator to start at 1
// If array is [2, 4, 6], the returned value in product
// will be 48 (1 * 2 * 4 * 6)js reduce
Sum array elements:
let myArr = [1,2,3,-1,-34,0]
return myArr.reduce((a,b) => a + b,0)javascript reduce
const sum = array.reduce((accumulator, element) => {
return accumulator + element;
}, 0);reduce javascript
/* this is our initial value i.e. the starting point*/
const initialValue = 0;
/* numbers array */
const numbers = [5, 10, 15];
/* reducer method that takes in the accumulator and next item */
const reducer = (accumulator, item) => {
return accumulator + item;
};
/* we give the reduce method our reducer function
and our initial value */
const total = numbers.reduce(reducer, initialValue)Copyright © 2021 Codeinu
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