Answers for "xhr request post"

0

xhr post

var url = "https://example.com/";

var xhr = new XMLHttpRequest();
xhr.open("POST", url);

xhr.setRequestHeader("Content-Type", "application/json");

xhr.onreadystatechange = function () {
   if (xhr.readyState === 4) {
      console.log(xhr.status);
      console.log(xhr.responseText);
   }};

var data = `{
	"name": "Bob"
}`;

xhr.send(data);
Posted by: Guest on June-11-2021
5

xhr post send

var xhr = new XMLHttpRequest();
var params = 'field1='+postfield1+'&field2='+postfield2;
xhr.open('POST', 'http://exmaple.com', true);

//Send the proper header information along with the request
xhr.setRequestHeader('Content-type', 'application/x-www-form-urlencoded');

xhr.onload = function() {//Call a function when the state changes.
    if(xhr.status == 200) {
        alert(this.responseText);
    }
}
xhr.send(params);
Posted by: Guest on July-15-2020
0

xmlhttp js post request

var xhr = new XMLHttpRequest();
xhr.open("POST", '/url', true);
xhr.setRequestHeader("Content-Type", "application/x-www-form-urlencoded");

xhr.onreadystatechange = function() { // Call a function when the state changes.
    if (this.readyState === XMLHttpRequest.DONE && this.status === 200) {
        // Request finished. Do processing here.
    }
}
xhr.send("name=Hello&id=world");
Posted by: Guest on May-26-2020

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