xhr post send
var xhr = new XMLHttpRequest();
var params = 'field1='+postfield1+'&field2='+postfield2;
xhr.open('POST', 'http://exmaple.com', true);
//Send the proper header information along with the request
xhr.setRequestHeader('Content-type', 'application/x-www-form-urlencoded');
xhr.onload = function() {//Call a function when the state changes.
if(xhr.status == 200) {
alert(this.responseText);
}
}
xhr.send(params);ajax open a request
<script>
function loadDoc() {
var xhttp = new XMLHttpRequest();
//looking for a change or state , like a request or get.
xhttp.onreadystatechange = function() {
//if equal to 4 means that its ready.
// if equal to 200 indicates that the request has succeeded.
if (this.readyState == 4 && this.status == 200) {
document.getElementById("demo").innerHTML = this.responseText;
}
};
//GET method for gettin the data // the file you are requesting
xhttp.open("GET", "TheFileYouWant.html", true);
//sending the request
xhttp.send();
}Copyright © 2021 Codeinu
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